7x^2-8-216=0

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Solution for 7x^2-8-216=0 equation:



7x^2-8-216=0
We add all the numbers together, and all the variables
7x^2-224=0
a = 7; b = 0; c = -224;
Δ = b2-4ac
Δ = 02-4·7·(-224)
Δ = 6272
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{6272}=\sqrt{3136*2}=\sqrt{3136}*\sqrt{2}=56\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-56\sqrt{2}}{2*7}=\frac{0-56\sqrt{2}}{14} =-\frac{56\sqrt{2}}{14} =-4\sqrt{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+56\sqrt{2}}{2*7}=\frac{0+56\sqrt{2}}{14} =\frac{56\sqrt{2}}{14} =4\sqrt{2} $

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